Solar Panel Sizing: How Many kW Do You Need?
20 kWh a day, 5 peak-sun hours and 80% system efficiency means a 5 kW array, or about 10 panels of 540 W. See the formula and the checks before you buy.
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20 kWh a day, 5 peak-sun hours and 80% system efficiency means a 5 kW array, or about 10 panels of 540 W. See the formula and the checks before you buy.
Three-phase apparent power in kVA = √3 × line voltage × line current ÷ 1,000. At 400 V and 25 A, a balanced load is about 17.32 kVA.
Single-phase apparent power in kVA = volts × amps ÷ 1,000. At 230 V and 20 A the load is 4.6 kVA, which is 92% of a 5 kVA transformer.
A 310 W desk setup needs about 517 VA on a 0.6 power-factor UPS, and a 12 V 100 Ah battery then keeps it up for around 2.6 hours. Here is how to size both.
A 2.5 mm² copper cable carrying 10 A over 20 m loses about 2.75 V, using ΔV = 2 × I × ρ × L ÷ A. Here is how to check, limit and fix the loss.
Wire size depends on current rating, run length and voltage drop. For 15 A over 20 m at 230 V, 2.5 mm² drops about 1.8%; on 12 V you need far more.
Explore our free calculators and apply these concepts to your own numbers.