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Power

Watts, kilowatt-hours and the bill:
power and energy explained

Understand the difference between power and energy, read an appliance label, and work out the units your meter will count.

Calcylator Editorial Team

Updated · 5 min read

Power is a rate, energy is the total

People often blur the two words, but they answer different questions. Power says how fast a device uses electrical energy at one instant, in watts. Energy says how much was used in total over a period, in joules or, on bills, in kilowatt-hours.

Think of power as a car's speed and energy as the distance covered. A 2,000 W heater is a statement about its draw. How much it adds to your bill depends on how long it runs.

Electrical power =P = V × I
P:
power in watts (W)
V:
voltage in volts (V)
I:
current in amperes (A)
For ordinary AC loads with inductive parts, real power is V × I × power factor.
  • Voltage

    230 V

  • Current

    8.7 A

Power

≈ 2,001 W, about 2.0 kW

230 × 8.7 = 2,001 W.

Energy, time and the kilowatt-hour

Energy =E = P × t
E:
energy in watt-hours, or kWh when P is in kW
t:
time in hours
1 kWh = 3.6 megajoules.

A kilowatt-hour is simply 1,000 watts used for one hour. On an electricity bill one billed unit is one kWh. Convert watts to kilowatts first, then multiply by hours.

  • Power

    2.0 kW (2,001 W)

  • Time

    3 hours

Energy used

≈ 6.0 kWh

2.001 × 3 = 6.003 kWh. At an assumed ₹7 per unit that is about ₹42. Your tariff, slabs and fixed charges will differ, so use your own bill's rate.

A quick check with an electrical energy calculator confirms the unit conversion, which is the step where most slips happen.

Estimating a month from a label

Appliance labels give watts or, sometimes, volts and amps. Multiply by daily hours and by days. The table uses typical illustrative ratings, so read your own device plate.

Appliance (typical)PowerUseEnergy per month (30 days)
LED bulb10 W5 h/day1.5 kWh
Ceiling fan75 W8 h/day18 kWh
Room heater1,500 W2 h/day90 kWh
Refrigerator (average draw)60 W24 h/day43.2 kWh

The heater row shows how one device can dominate: 1.5 kW × 2 h × 30 days = 90 kWh, which at ₹7 per unit would be around ₹630. Compressor loads like refrigerators cycle on and off, so their average draw is far below the label's peak figure.

Checking a load against the meter

Energy meters usually have a pulse LED marked in impulses per kWh. Counting pulses over a known time gives the power of whatever is running. A meter marked 1,600 imp/kWh that flashes 80 times in 60 seconds has recorded 80 ÷ 1,600 = 0.05 kWh in one minute.

  • Meter constant

    1,600 imp/kWh

  • Pulses counted

    80 in 60 s

Power drawn

3.0 kW

0.05 kWh × 60 minutes per hour = 3.0 kW.

Switch off other loads before the test, or the figure will include them. The method is a handy way to check a label, spot a fault drawing more than it should, or test whether a standby load is worth worrying about.

Other forms of the same equation

Combine P = V × I with Ohm's law (V = I × R) and you get two more forms that are useful when only one of the quantities is known.

  • P = I² × R: heat produced in a resistor or a cable, which is why thin wires carrying large current get hot.
  • P = V² ÷ R: a fixed-resistance heater at a given supply voltage.

For a 230 V heater element of 26.45 Ω, V² ÷ R = 52,900 ÷ 26.45 = 2,000 W. Note that if the supply voltage drops by 10 percent, the power drops by about 19 percent because voltage is squared.

Where the estimate can be off

  • Power factor: motors and some power supplies draw more apparent power (VA) than real power (W). Bills for households are based on real energy.
  • Variable loads: air conditioners and refrigerators cycle, so use measured kWh from a plug-in meter where possible.
  • Standby draw: devices left plugged in use a small amount continuously.
  • Tariffs: slabs, time-of-day rates and fixed charges mean cost is not always units × a single rate.

Watt-hours for batteries and backup power

Battery capacity is quoted in amp-hours, which only becomes energy once you multiply by voltage. A 12 V, 100 Ah battery holds 12 × 100 = 1,200 Wh, or 1.2 kWh. A 150 W load would drain that in 8 hours on paper.

Real use is shorter. If only 80 percent of the capacity is safely usable and the inverter is 85 percent efficient, the available energy is 1,200 × 0.8 × 0.85 = 816 Wh, which runs the same load for about 5.4 hours. The percentages here are illustrative, so use the datasheet for your own equipment.

  • Amp-hours times volts gives watt-hours.
  • Divide usable watt-hours by load watts to get hours of backup.
  • Add the loads you plan to run together, and allow for start-up surges in motors and compressors.

From watts back to amperes

The formula also runs in reverse, and this is how you check a circuit. Current is power divided by voltage: a 3 kW water heater at 230 V draws 3,000 ÷ 230 = 13.0 A, and a 2 kW heater draws 8.7 A.

LoadVoltageCurrent
500 W230 V2.2 A
1,000 W230 V4.3 A
2,000 W230 V8.7 A
3,000 W230 V13.0 A

Add up the currents on a circuit and compare the total with the rating of the wire, the socket and the breaker. A socket rated for 16 A at 230 V can supply up to 3,680 W, and continuous loads should sit comfortably below that limit. Cables heat in proportion to I² × R, so doubling the current quadruples the heating in the same wire.

It also helps to connect these figures to a month's bill in practice. Add up the kWh of your major appliances using hours of real use, compare the sum with the units on your last bill, and the gap shows how much comes from standby loads, cycling devices and estimates that were too generous. Repeating the check after a change, such as a new air conditioner or a switch to LED lighting, tells you whether the saving actually appeared.

Common questions

What is the formula for electrical power?

Power in watts equals voltage in volts multiplied by current in amperes, P = V × I. A device at 230 V drawing 8.7 A uses about 2,001 W, or 2 kW. For AC loads include power factor.

How do you convert watts to kWh?

Divide watts by 1,000 to get kilowatts, then multiply by hours of use. A 1,500 W heater running for 2 hours uses 1.5 × 2 = 3 kWh. One kWh is what electricity bills commonly call a unit.

How many units does a 1,000 watt appliance use in an hour?

Exactly one unit, which is 1 kWh. Run it for 10 hours and it uses 10 units. Units billed equal power in kilowatts multiplied by hours, regardless of the appliance type.

What is the difference between kW and kWh?

A kilowatt measures power, the rate of using energy at a moment. A kilowatt-hour measures energy, the amount used over time. A 2 kW heater running for 3 hours uses 6 kWh.

How do I estimate the monthly cost of an appliance?

Multiply its power in kW by daily hours and by 30 for monthly kWh, then multiply by your tariff per unit. A 1.5 kW heater for 2 hours a day is 90 kWh a month, before any fixed charges.

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